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On the number of k-skip-n-grams
May 14, 2019 ยท Declared Dead ยท ๐ arXiv.org
"No code URL or promise found in abstract"
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Authors
Dmytro Krasnoshtan
arXiv ID
1905.05407
Category
cs.CL: Computation & Language
Citations
0
Venue
arXiv.org
Last Checked
6 months ago
Abstract
The paper proves that the number of k-skip-n-grams for a corpus of size $L$ is $$\frac{Ln + n + k' - n^2 - nk'}{n} \cdot \binom{n-1+k'}{n-1}$$ where $k' = \min(L - n + 1, k)$.
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