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The Ethereal
On Mappings on the Hypercube with Small Average Stretch
May 27, 2019 · The Ethereal · 🏛 Combinatorics, probability & computing
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Authors
Lucas Boczkowski, Igor Shinkar
arXiv ID
1905.11350
Category
math.CO: Combinatorics
Cross-listed
cs.DS
Citations
1
Venue
Combinatorics, probability & computing
Last Checked
3 months ago
Abstract
Let $A \subseteq \{0,1\}^n$ be a set of size $2^{n-1}$, and let $φ\colon \{0,1\}^{n-1} \to A$ be a bijection. We define the average stretch of $φ$ as ${\sf avgStretch}(φ) = {\mathbb E}[{\sf dist}(φ(x),φ(x'))]$, where the expectation is taken over uniformly random $x,x' \in \{0,1\}^{n-1}$ that differ in exactly one coordinate. In this paper we continue the line of research studying mappings on the discrete hypercube with small average stretch. We prove the following results. (1) For any set $A \subseteq \{0,1\}^n$ of density $1/2$ there exists a bijection $φ_A \colon \{0,1\}^{n-1} \to A$ such that ${\sf avgstretch}(φ_A) = O(\sqrt{n})$. (2) For $n = 3^k$ let $A_{{\sf rec\text{-}maj}} = \{x \in \{0,1\}^n : {\sf rec\text{-}maj}(x) = 1\}$, where ${\sf rec\text{-}maj} : \{0,1\}^n \to \{0,1\}$ is the function recursive majority of 3's. There exists a bijection $φ_{{\sf rec\text{-}maj}} \colon \{0,1\}^{n-1} \to A_{\sf rec\text{-}maj}$ such that ${\sf avgstretch}(φ_{\sf rec\text{-}maj}) = O(1)$. (3) Let $A_{\sf tribes} = \{x \in \{0,1\}^n : {\sf tribes}(x) = 1\}$. There exists a bijection $φ_{\sf tribes} \colon \{0,1\}^{n-1} \to A_{\sf tribes}$ such that ${\sf avgstretch}(φ_{\sf tribes}) = O(\log(n))$. These results answer the questions raised by Benjamini et al.\ (FOCS 2014).
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