The Communication Complexity of Set Intersection and Multiple Equality Testing
August 30, 2019 Β· Declared Dead Β· π ACM-SIAM Symposium on Discrete Algorithms
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Authors
Dawei Huang, Seth Pettie, Yixiang Zhang, Zhijun Zhang
arXiv ID
1908.11825
Category
cs.IT: Information Theory
Cross-listed
cs.CC
Citations
21
Venue
ACM-SIAM Symposium on Discrete Algorithms
Last Checked
5 months ago
Abstract
In this paper we explore fundamental problems in randomized communication complexity such as computing Set Intersection on sets of size $k$ and Equality Testing between vectors of length $k$. SaΔlam and Tardos and Brody et al. showed that for these types of problems, one can achieve optimal communication volume of $O(k)$ bits, with a randomized protocol that takes $O(\log^* k)$ rounds. Aside from rounds and communication volume, there is a \emph{third} parameter of interest, namely the \emph{error probability} $p_{\mathrm{err}}$. It is straightforward to show that protocols for Set Intersection or Equality Testing need to send $Ξ©(k + \log p_{\mathrm{err}}^{-1})$ bits. Is it possible to simultaneously achieve optimality in all three parameters, namely $O(k + \log p_{\mathrm{err}}^{-1})$ communication and $O(\log^* k)$ rounds? In this paper we prove that there is no universally optimal algorithm, and complement the existing round-communication tradeoffs with a new tradeoff between rounds, communication, and probability of error. In particular: 1. Any protocol for solving Multiple Equality Testing in $r$ rounds with failure probability $2^{-E}$ has communication volume $Ξ©(Ek^{1/r})$. 2. There exists a protocol for solving Multiple Equality Testing in $r + \log^*(k/E)$ rounds with $O(k + rEk^{1/r})$ communication, thereby essentially matching our lower bound and that of SaΔlam and Tardos. Our original motivation for considering $p_{\mathrm{err}}$ as an independent parameter came from the problem of enumerating triangles in distributed ($\textsf{CONGEST}$) networks having maximum degree $Ξ$. We prove that this problem can be solved in $O(Ξ/\log n + \log\log Ξ)$ time with high probability $1-1/\operatorname{poly}(n)$.
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