Hutchinson's Estimator is Bad at Kronecker-Trace-Estimation
September 10, 2023 Β· Declared Dead Β· π arXiv.org
"No code URL or promise found in abstract"
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Authors
Raphael A. Meyer, Haim Avron
arXiv ID
2309.04952
Category
cs.DS: Data Structures & Algorithms
Cross-listed
math.NA
Citations
3
Venue
arXiv.org
Last Checked
4 months ago
Abstract
We study the problem of estimating the trace of a matrix $\mathbf{A}$ that can only be accessed through Kronecker-matrix-vector products. That is, for any Kronecker-structured vector $\mathrm{x} = \otimes_{i=1}^k \mathrm{x}_i$, we can compute $\mathbf{A}\mathrm{x}$. We focus on the natural generalization of Hutchinson's Estimator to this setting, proving tight rates for the number of matrix-vector products this estimator needs to find a $(1\pm\varepsilon)$ approximation to the trace of $\mathbf{A}$. We find an exact equation for the variance of the estimator when using a Kronecker of Gaussian vectors, revealing an intimate relationship between Hutchinson's Estimator, the partial trace operator, and the partial transpose operator. Using this equation, we show that when using real vectors, in the worst case, this estimator needs $O(\frac{3^k}{\varepsilon^2})$ products to recover a $(1\pm\varepsilon)$ approximation of the trace of any PSD $\mathbf{A}$, and a matching lower bound for certain PSD $\mathbf{A}$. However, when using complex vectors, this can be exponentially improved to $Ξ(\frac{2^k}{\varepsilon^2})$. Further, if the $\mathrm{x}_i$ vectors are low-dimensional and if we instead build $\mathrm{x}$ as the Kronecker product of (scaled) random unit vectors on the complex sphere, then as few as $\frac{1.33^k}{\varepsilon^2}$ samples suffice. We show that Hutchinson's Estimator converges slowest when $\mathbf{A}$ itself also has Kronecker structure. We conclude with some theoretical evidence suggesting that, by combining Hutchinson's Estimator with other techniques, it may be possible to avoid the exponential dependence on $k$.
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