Every latin hypercube of order 5 has transversals

November 25, 2023 ยท The Ethereal ยท ๐Ÿ› Journal of combinatorial designs (Print)

๐Ÿ”ฎ THE ETHEREAL: The Ethereal
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Authors A. L. Perezhogin, V. N. Potapov, S. Yu. Vladimirov arXiv ID 2311.14997 Category math.CO: Combinatorics Cross-listed cs.IT Citations 1 Venue Journal of combinatorial designs (Print) Last Checked 3 months ago
Abstract
We prove that for all n>1 every latin n-dimensional cube of order 5 has transversals. We find all 123 paratopy classes of layer-latin cubes of order 5 with no transversals. For each $n\geq 3$ and $q\geq 3$ we construct a (2q-2)-layer latin n-dimensional cuboid with no transversals. Moreover, we find all paratopy classes of nonextendible and noncompletable latin cuboids of order 5.
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