Weakly Approximating Knapsack in Subquadratic Time
April 21, 2025 Β· Declared Dead Β· π International Colloquium on Automata, Languages and Programming
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Authors
Lin Chen, Jiayi Lian, Yuchen Mao, Guochuan Zhang
arXiv ID
2504.15001
Category
cs.DS: Data Structures & Algorithms
Citations
1
Venue
International Colloquium on Automata, Languages and Programming
Last Checked
4 months ago
Abstract
We consider the classic Knapsack problem. Let $t$ and $\mathrm{OPT}$ be the capacity and the optimal value, respectively. If one seeks a solution with total profit at least $\mathrm{OPT}/(1 + \varepsilon)$ and total weight at most $t$, then Knapsack can be solved in $\tilde{O}(n + (\frac{1}{\varepsilon})^2)$ time [Chen, Lian, Mao, and Zhang '24][Mao '24]. This running time is the best possible (up to a logarithmic factor), assuming that $(\min,+)$-convolution cannot be solved in truly subquadratic time [KΓΌnnemann, Paturi, and Schneider '17][Cygan, Mucha, WΔgrzycki, and WΕodarczyk '19]. The same upper and lower bounds hold if one seeks a solution with total profit at least $\mathrm{OPT}$ and total weight at most $(1 + \varepsilon)t$. Therefore, it is natural to ask the following question. If one seeks a solution with total profit at least $\mathrm{OPT}/(1+\varepsilon)$ and total weight at most $(1 + \varepsilon)t$, can Knsapck be solved in $\tilde{O}(n + (\frac{1}{\varepsilon})^{2-Ξ΄})$ time for some constant $Ξ΄> 0$? We answer this open question affirmatively by proposing an $\tilde{O}(n + (\frac{1}{\varepsilon})^{7/4})$-time algorithm.
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