A Simple PTAS for Weighted $k$-means and Sensor Coverage

August 08, 2025 Β· Declared Dead Β· πŸ› arXiv.org

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Authors Akash Pareek, Supratim Shit arXiv ID 2508.06460 Category cs.DS: Data Structures & Algorithms Citations 0 Venue arXiv.org Last Checked 4 months ago
Abstract
Clustering is a fundamental technique in data analysis, with the $k$-means being one of the widely studied objectives due to its simplicity and broad applicability. In many practical scenarios, data points come with associated weights that reflect their importance, frequency, or confidence. Given a weighted point set $P \subset R^d$, where each point $p \in P$ has a positive weight $w_p$, the goal is to compute a set of $k$ centers $C = \{ c_1, c_2, \ldots, c_k \} \subset R^d$ that minimizes the weighted clustering cost: $Ξ”_w(P,C) = \sum_{p \in P} w_p \cdot d(p,C)^2$, where $d(p,C)$ denotes the Euclidean distance from $p$ to its nearest center in $C$. Although most existing coreset-based algorithms for $k$-means extend naturally to the weighted setting and provide a PTAS, no prior work has offered a simple, coreset-free PTAS designed specifically for the weighted $k$-means problem. In this paper, we present a simple PTAS for weighted $k$-means that does not rely on coresets. Building upon the framework of Jaiswal, Kumar, and Sen (2012) for the unweighted case, we extend the result to the weighted setting by using the weighted $D^2$-sampling technique. Our algorithm runs in time $n d \cdot 2^{O\left(\frac{k^2}Ξ΅\right)}$ and outputs a set of $k$ centers whose total clustering cost is within a $(1 + Ξ΅)$-factor of the optimal cost. As a key application of the weighted $k$-means, we obtain a PTAS for the sensor coverage problem, which can also be viewed as a continuous locational optimization problem. For this problem, the best-known result prior to our work was an $O(\log k)$-approximation by Deshpande (2014), whereas our algorithm guarantees a $(1 + Ξ΅)$-approximation to the optimal coverage cost even before applying refinement steps like Lloyd desent.
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